|
|
这里是一个科氏效应对理论弹道（不考虑大气和重力的因素）的影响计算公式。注意是对正南北向发射。
References:
Principles of Naval Weapon Systems by Craig M. Payne
For ranges up to 20,000 yards (18.2 km / 11.3 miles); the Coriolis force does not seriously affect fire control solutions. Beyond this however, the rotation of the earth has an increasing effect.
In the northern hemisphere, the displacement occurs to the right, while in the south it displaces to the left.
Computing Coriolis Acceleration on Earth
AccelerationCoriolis = 2 * Velocity * RateRotation
RateRotation = (2 * Pi / 86,400 Seconds) * Sin(Latitude)
Where:
AccelerationCoriolis = Coriolis Acceleration in m/sec.
Velocity: Speed of Projectile in m/sec.
Latitude: Latitude in Radians (e.g. if you had 40 Degrees North Latitude, it would be 0.7 Radians North).
86,400 Seconds: The Earth's rotational period is 24 hours, and each hour has 3,600 seconds; thus 86,400 seconds.
Computing Displaced Distance Due to the Coriolis Effect:
DistanceDisplaced = 0.5 * AccelerationCoriolis * TOF 2(square)
Where:
DistanceDisplaced: Distance displaced due to Coriolis Effect in Meters
AccelerationCoriolis: Acceleration due to Coriolis effect (previously calculated)
TOF: Time of Flight in seconds.
EXAMPLES: What is the displacement of artillery shells fired at 700 m/sec from a position at 20N Latitude (0.35 rad) with flight times of 35, 60, and 80 seconds respectively?
RateRotation = (2 * PI / 86,400 Sec) * Sin (0.35) = 0.0348 m/sec
Displaced Distance I: 0.5 * 0.0348 * 35 2(square) = 21.33 meters
Displaced Distance II: 0.5 * 0.0348 * 60 2(square) = 62.68 meters
Displaced Distance III: 0.5 * 0.0348 * 80 2(square) = 111.43 meters
|
|
发表于 2013-9-1 21:28
发表于 2013-9-1 21:50
发表于 2013-9-2 00:52
楼主